1886 Belgian general election explained

Election Name:1886 Belgian general election
Country:Belgium
Type:parliamentary
Previous Election:1884 Belgian general election
Previous Year:1884
Next Election:1888 Belgian general election
Next Year:1888
Seats For Election:69 of the 138 seats in the Chamber of Representatives
Majority Seats:70
Leader1:Auguste Beernaert
Leader Since1:Candidate for PM
Party1:Catholic Party (Belgium)
Seats Before1:86 seats
Seats1:32
Seats After1:98
Seat Change1: 12
Popular Vote1:17,979
Percentage1:48.67%
Party2:Liberal Party (Belgium)
Seats Before2:52 seats
Seats2:37
Seats After2:40
Seat Change2: 12
Popular Vote2:18,965
Percentage2:51.33%
Government
Posttitle:Government after election
Before Election:Beernaert
Before Party:Catholic Party (Belgium)
After Election:Beernaert
After Party:Catholic Party (Belgium)

Partial general elections were held in Belgium on 8 June 1886.[1] [2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 98 of the 138 seats.[2]

Under the alternating system, elections were only held in four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders.

The Catholics continued their gains, after the 1884 elections that gave them a victory over the Liberals. With the defeat of the Liberals by the Catholics in the eight-member arrondissement of Ghent, the Catholics now had all "Flemish" seats. Catholics also gained both seats of the arrondissement of Waremme and two out of seven in the arrondissement of Charleroi.

Results

Chamber of Representatives

Notes and References

  1. Codebook Constituency-level Elections Archive, 2003
  2. Sternberger, D, Vogel, B & Nohlen, D (1969) Die Wahl der Parlamente: Band I: Europa - Erster Halbband, p105