See main article: article and 1884 United States presidential election.
| Election Name: | 1884 United States presidential election in Minnesota |
| Country: | Minnesota |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1880 United States presidential election in Minnesota |
| Previous Year: | 1880 |
| Election Date: | November 4, 1884 |
| Next Election: | 1888 United States presidential election in Minnesota |
| Next Year: | 1888 |
| Image1: | Unsuccessful 1884.jpg |
| Nominee1: | James G. Blaine |
| Party1: | Republican Party (United States) |
| Home State1: | Maine |
| Running Mate1: | John A. Logan |
| Electoral Vote1: | 7 |
| Popular Vote1: | 111,865 |
| Percentage1: | 58.78% |
| Nominee2: | Grover Cleveland |
| Running Mate2: | Thomas A. Hendricks |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Electoral Vote2: | 0 |
| Popular Vote2: | 70,065 |
| Percentage2: | 36.87% |
| Map Size: | 350px |
| President | |
| Before Election: | Chester A. Arthur |
| Before Party: | Republican Party (United States) |
| After Election: | Grover Cleveland |
| After Party: | Democratic Party (United States) |
| Flag Image: | Flag of Minnesota (1893–1957).svg |
The 1884 United States presidential election in Minnesota took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Minnesota was won by Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 21.91%.
With 58.78% of the popular vote, Minnesota would prove to be Blaine's second strongest victory in terms of percentage in the popular vote after Vermont.[1]
As of 2020, this remains the last time that a Republican presidential nominee would win a majority of the vote in Minnesota while losing nationally.