See main article: 1884 United States presidential election.
| Election Name: | 1884 United States presidential election in Delaware |
| Country: | Delaware |
| Flag Year: | 1884 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1880 United States presidential election in Delaware |
| Previous Year: | 1880 |
| Next Election: | 1888 United States presidential election in Delaware |
| Next Year: | 1888 |
| Election Date: | November 4, 1884 |
| Image1: | StephenGroverCleveland.png |
| Nominee1: | Grover Cleveland |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Thomas A. Hendricks |
| Electoral Vote1: | 3 |
| Popular Vote1: | 16,957 |
| Percentage1: | 56.55% |
| Nominee2: | James G. Blaine |
| Party2: | Republican Party (United States) |
| Home State2: | Maine |
| Running Mate2: | John A. Logan |
| Electoral Vote2: | 0 |
| Popular Vote2: | 12,953 |
| Percentage2: | 43.20% |
| Map Size: | 210px |
| President | |
| Before Election: | Chester A. Arthur |
| Before Party: | Republican Party (United States) |
| After Election: | Grover Cleveland |
| After Party: | Democratic Party (United States) |
The 1884 United States presidential election in Delaware took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Delaware voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a margin of 13.35%.