1884 United States presidential election in Connecticut explained

See main article: 1884 United States presidential election.

Election Name:1884 United States presidential election in Connecticut
Country:Connecticut
Type:presidential
Ongoing:no
Previous Election:1880 United States presidential election in Connecticut
Previous Year:1880
Next Election:1888 United States presidential election in Connecticut
Next Year:1888
Election Date:November 4, 1884
Image1:StephenGroverCleveland.png
Nominee1:Grover Cleveland
Party1:Democratic Party (United States)
Home State1:New York
Running Mate1:Thomas A. Hendricks
Electoral Vote1:6
Popular Vote1:67,182
Percentage1:48.95%
Nominee2:James G. Blaine
Party2:Republican Party (United States)
Home State2:Maine
Running Mate2:John A. Logan
Electoral Vote2:0
Popular Vote2:65,898
Percentage2:48.01%
Map Size:250px
President
Before Election:Chester A. Arthur
Before Party:Republican Party (United States)
After Election:Grover Cleveland
After Party:Democratic Party (United States)

The 1884 United States presidential election in Connecticut took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.

Connecticut voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. Cleveland won the state by a very narrow margin of 0.94%. Cleveland was the first Democrat to win without New London County since 1844 and Middlesex County since 1832.

See also