1881 Buffalo mayoral election explained

Election Name:Buffalo mayoral election, 1881
Type:presidential
Ongoing:no
Previous Year:1879
Next Year:1883 (special)
Nominee1:Grover Cleveland
Party1:Democratic Party (United States)
Popular Vote1:15,120
Percentage1:56.74%
Nominee2:Milton Beebe
Party2:Republican Party (United States)
Popular Vote2:11,528
Percentage2:43.26%
Mayor
Before Election:Alexander Brush
Before Party:Republican Party (United States)
After Election:Grover Cleveland
After Party:Democratic Party (United States)

The Buffalo mayoral election of 1881 saw the election of former Erie County Sheriff Grover Cleveland, who defeated architect and alderman Milton Beebe by what was considered a broad margin.[1]

Cleveland would not serve out his entire term as mayor, as he would be subsequently elected Governor of New York the following year.

Notes and References

  1. Web site: Przepasniak . Ellen . Jan. 2, 1882: Grover Cleveland begins brief term as mayor of Buffalo . Buffalo News . 11 October 2019 . 2 January 2019.