See main article: 1880 United States presidential election.
Election Name: | 1880 United States presidential election in Missouri |
Country: | Missouri |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1876 United States presidential election in Missouri |
Previous Year: | 1876 |
Next Election: | 1884 United States presidential election in Missouri |
Next Year: | 1884 |
Election Date: | November 2, 1880 |
Image1: | WinfieldScottHancock2 (cropped 3x4).jpg |
Nominee1: | Winfield S. Hancock |
Party1: | Democratic Party (United States) |
Home State1: | Pennsylvania |
Running Mate1: | William H. English |
Electoral Vote1: | 15 |
Popular Vote1: | 208,600 |
Percentage1: | |
Nominee2: | James A. Garfield |
Party2: | Republican Party (United States) |
Home State2: | Ohio |
Running Mate2: | Chester A. Arthur |
Electoral Vote2: | 0 |
Popular Vote2: | 153,647 |
Image3: | James Weaver - Brady-Handy (cropped 3x4).jpg |
Nominee3: | James B. Weaver |
Party3: | Greenback Party |
Home State3: | Iowa |
Running Mate3: | Barzillai J. Chambers |
Electoral Vote3: | 0 |
Popular Vote3: | 35,042 |
Percentage3: | 8.82% |
Map Size: | 340px |
President | |
Before Election: | Rutherford B. Hayes |
Before Party: | Republican Party (United States) |
After Election: | James A. Garfield |
After Party: | Republican Party (United States) |
The 1880 United States presidential election in Missouri took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
Missouri voted for the Democratic nominee, Winfield Scott Hancock, over the Republican nominee, James A. Garfield by a margin of 13.84%.