See main article: 1880 United States presidential election.
| Election Name: | 1880 United States presidential election in Massachusetts |
| Country: | Massachusetts |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1876 United States presidential election in Massachusetts |
| Previous Year: | 1876 |
| Next Election: | 1884 United States presidential election in Massachusetts |
| Turnout: | 71.2%[1] 1.1 pp |
| Next Year: | 1884 |
| Election Date: | November 2, 1880 |
| Image1: | James Abram Garfield, photo portrait seated (cropped).jpg |
| Nominee1: | James A. Garfield |
| Party1: | Republican Party (United States) |
| Home State1: | Ohio |
| Running Mate1: | Chester A. Arthur |
| Electoral Vote1: | 13 |
| Popular Vote1: | 165,198 |
| Percentage1: | 58.53% |
| Nominee2: | Winfield S. Hancock |
| Party2: | Democratic Party (United States) |
| Home State2: | Pennsylvania |
| Running Mate2: | William H. English |
| Electoral Vote2: | 0 |
| Popular Vote2: | 111,720 |
| Percentage2: | 39.58% |
| Map Size: | 350px |
| President | |
| Before Election: | Rutherford B. Hayes |
| Before Party: | Republican Party (United States) |
| After Election: | James A. Garfield |
| After Party: | Republican Party (United States) |
The 1880 United States presidential election in Massachusetts took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.
Massachusetts voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 18.95%.