See main article: 1880 United States presidential election.
| Election Name: | 1880 United States presidential election in Alabama |
| Country: | Alabama |
| Flag Year: | 1861 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1876 United States presidential election in Alabama |
| Previous Year: | 1876 |
| Next Election: | 1884 United States presidential election in Alabama |
| Next Year: | 1884 |
| Election Date: | November 2, 1880 |
| Turnout: | 12.03% of the total population 5.19 pp[1] |
| Image1: | WinfieldScottHancock2 (cropped 3x4).jpg |
| Nominee1: | Winfield S. Hancock |
| Party1: | Democratic Party (United States) |
| Home State1: | Pennsylvania |
| Running Mate1: | William H. English |
| Electoral Vote1: | 10 |
| Popular Vote1: | 91,130 |
| Percentage1: | 59.99% |
| Nominee2: | James A. Garfield |
| Party2: | Republican Party (United States) |
| Home State2: | Ohio |
| Running Mate2: | Chester A. Arthur |
| Electoral Vote2: | 0 |
| Popular Vote2: | 56,350 |
| Percentage2: | 37.10% |
| Map Size: | 200px |
| President | |
| Before Election: | Rutherford B. Hayes |
| Before Party: | Republican Party (United States) |
| After Election: | James A. Garfield |
| After Party: | Republican Party (United States) |
The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee, Chester A. Arthur, with 37.10% of the vote.[2]