| Election Name: | 1880 Rhode Island gubernatorial election |
| Country: | Rhode Island |
| Flag Year: | 1877 |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1879 Rhode Island gubernatorial election |
| Previous Year: | 1879 |
| Next Election: | 1881 Rhode Island gubernatorial election |
| Next Year: | 1881 |
| Election Date: | April 7, 1880 |
| Nominee1: | Alfred H. Littlefield |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 10,224 |
| Percentage1: | 44.82% |
| Nominee2: | Horace A. Kimball |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 7,440 |
| Percentage2: | 32.62% |
| Nominee3: | Albert C. Howard |
| Party3: | Independent Republican (United States) |
| Popular Vote3: | 5,047 |
| Percentage3: | 22.13% |
| Map Size: | 225px |
| Governor | |
| Before Election: | Charles C. Van Zandt |
| Before Party: | Republican Party (United States) |
| After Election: | Alfred H. Littlefield |
| After Party: | Republican Party (United States) |
The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.
Major party candidates
Other candidates