1877 Iowa gubernatorial election explained

Election Name:1877 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1875 Iowa gubernatorial election
Previous Year:1875
Next Election:1879 Iowa gubernatorial election
Next Year:1879
Election Date:October 9, 1877
Nominee1:John H. Gear
Party1:Republican Party (United States)
Popular Vote1:121,316
Percentage1:49.39%
Nominee2:John P. Irish
Party2:Democratic Party (United States)
Popular Vote2:79,304
Percentage2:32.29%
Nominee3:Daniel P. Stubbs
Party3:Greenback Party
Popular Vote3:34,316
Percentage3:13.97%
Map Size:240px
Governor
Before Election:Joshua G. Newbold
Before Party:Republican Party (United States)
After Election:John H. Gear
After Party:Republican Party (United States)

The 1877 Iowa gubernatorial election was held on October 9, 1877. Republican nominee John H. Gear defeated Democratic nominee John P. Irish with 49.39% of the vote.

General election

Candidates

Major party candidates

Other candidates