See main article: 1876 United States presidential election.
| Election Name: | 1876 United States presidential election in Vermont |
| Country: | Vermont |
| Flag Year: | 1837 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1872 United States presidential election in Vermont |
| Previous Year: | 1872 |
| Next Election: | 1880 United States presidential election in Vermont |
| Next Year: | 1880 |
| Election Date: | November 7, 1876 |
| Image1: | President Rutherford Hayes 1870 - 1880 Restored (cropped).jpg |
| Nominee1: | Rutherford B. Hayes |
| Party1: | Republican Party (United States) |
| Home State1: | Ohio |
| Running Mate1: | William A. Wheeler |
| Electoral Vote1: | 5 |
| Popular Vote1: | 44,091 |
| Percentage1: | 68.30% |
| Nominee2: | Samuel J. Tilden |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Running Mate2: | Thomas A. Hendricks |
| Electoral Vote2: | 0 |
| Popular Vote2: | 20,254 |
| Percentage2: | 31.38% |
| President | |
| Before Election: | Ulysses S. Grant |
| Before Party: | Republican Party (United States) |
| After Election: | Rutherford B. Hayes |
| After Party: | Republican Party (United States) |
The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.
With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.[1]