See main article: 1876 United States presidential election.
| Election Name: | 1876 United States presidential election in Nebraska |
| Country: | Nebraska |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1872 United States presidential election in Nebraska |
| Previous Year: | 1872 |
| Next Election: | 1880 United States presidential election in Nebraska |
| Next Year: | 1880 |
| Election Date: | November 7, 1876 |
| Image1: | President Rutherford Hayes 1870 - 1880 Restored (cropped).jpg |
| Nominee1: | Rutherford B. Hayes |
| Party1: | Republican Party (United States) |
| Home State1: | Ohio |
| Running Mate1: | William A. Wheeler |
| Electoral Vote1: | 3 |
| Popular Vote1: | 31,915 |
| Percentage1: | 64.70% |
| Nominee2: | Samuel J. Tilden |
| Party2: | Democratic Party (United States) |
| Home State2: | New York |
| Running Mate2: | Thomas A. Hendricks |
| Electoral Vote2: | 0 |
| Popular Vote2: | 17,413 |
| Percentage2: | 35.30% |
| Map Size: | 400px |
| President | |
| Before Election: | Ulysses S. Grant |
| Before Party: | Republican Party (United States) |
| After Election: | Rutherford B. Hayes |
| After Party: | Republican Party (United States) |
The 1876 United States presidential election in Nebraska took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Nebraska voted for the Republican nominee, Ohio Governor Rutherford B. Hayes, over the Democratic nominee, New York Governor Samuel J. Tilden by a margin of 29.4%.
With 64.70% of the popular vote, Nebraska would be Hayes' second strongest victory in terms of percentage in the popular vote after Vermont.[1]