1872 United States presidential election in Tennessee explained

See main article: 1872 United States presidential election.

Election Name:1872 United States presidential election in Tennessee
Type:presidential
Ongoing:no
Previous Election:1868 United States presidential election in Tennessee
Previous Year:1868
Next Election:1876 United States presidential election in Tennessee
Next Year:1876
Election Date:November 5, 1872
Image1:Horace Greeley restored (cropped).jpg
Nominee1:Horace Greeley
Party1:Liberal Republican Party (United States)
Home State1:New York
Running Mate1:Benjamin G. Brown
Electoral Vote1:0
Popular Vote1:93,391
Percentage1:52.16%
Nominee2:Ulysses S. Grant
Popular Vote2:85,655
Percentage2:47.84%
Party2:Republican Party (United States)
Home State2:Ohio
Running Mate2:Henry Wilson
Electoral Vote2:0
Nominee3:Thomas A. Hendricks
Party3:Democratic Party (United States)
Home State3:Indiana
Running Mate3:-
Electoral Vote3:12
Map Size:350px
President
Before Election:Ulysses S. Grant
Before Party:Republican Party (United States)
After Election:Ulysses S. Grant
After Party:Republican Party (United States)

The 1872 United States presidential election in Tennessee took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

Tennessee voted for the Liberal Republican candidate, Horace Greeley, over Republican candidate, Ulysses S. Grant. Greeley won Tennessee by a margin of 4.32%. However, Greeley died prior to the Electoral College meeting, allowing for Tennessee's twelve electors to vote for the candidate of their choice.[1]

See also

Notes and References

  1. Web site: American presidential election, 1872. Encyclopædia Britannica. 5 December 2017.