1872 United States presidential election in New Jersey explained

See main article: 1872 United States presidential election.

Election Name:1872 United States presidential election in New Jersey
Country:New Jersey
Type:presidential
Ongoing:no
Previous Election:1868 United States presidential election in New Jersey
Previous Year:1868
Next Election:1876 United States presidential election in New Jersey
Next Year:1876
Election Date:November 5, 1872
Image1:UlyssesGrant.jpg
Nominee1:Ulysses S. Grant
Party1:Republican Party (United States)
Home State1:Illinois
Running Mate1:Henry Wilson
Electoral Vote1:9
Popular Vote1:91,656
Percentage1:54.52%
Nominee2:Horace Greeley
Party2:Liberal Republican Party (United States)
Colour2:C154C1
Home State2:New York
Running Mate2:Benjamin G. Brown
Electoral Vote2:0
Popular Vote2:76,456
Percentage2:45.48%
Map Size:350px
President
Before Election:Ulysses S. Grant
Before Party:Republican Party (United States)
After Election:Ulysses S. Grant
After Party:Republican Party (United States)

The 1872 United States presidential election in New Jersey took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose nine electors to the Electoral College, which selected the president and vice president.

New Jersey was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri by a margin of 9.04%.

This was the first time the Republicans won all the electoral votes of New Jersey, (see 1860 election in New Jersey for more information) as well as the popular vote. They would not win either again until 1896, 24 years later.

See also