1872 United States presidential election in Kentucky explained

See main article: 1872 United States presidential election.

Election Name:1872 United States presidential election in Kentucky
Flag Year:1872
Type:presidential
Ongoing:no
Previous Election:1868 United States presidential election in Kentucky
Previous Year:1868
Next Election:1876 United States presidential election in Kentucky
Next Year:1876
Election Date:November 5, 1872
Image1:Horace Greeley restored (cropped).jpg
Nominee1:Horace Greeley
Party1:Liberal Republican Party (United States)
Home State1:New York
Running Mate1:Benjamin G. Brown
Electoral Vote1:0
Popular Vote1:99,995
Percentage1:52.32%
Nominee2:Ulysses S. Grant
Party2:Republican Party (United States)
Home State2:Illinois
Running Mate2:Henry Wilson
Electoral Vote2:0
Popular Vote2:88,766
Percentage2:46.44%
Map Size:380px
President
Before Election:Ulysses S. Grant
Before Party:Republican Party (United States)
After Election:Ulysses S. Grant
After Party:Republican Party (United States)

The 1872 United States presidential election in Kentucky took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

Kentucky voted for the Liberal Republican candidate, Horace Greeley, over Republican candidate, Ulysses S. Grant. Greeley won Kentucky by a margin of 5.88%. However, Greeley died prior to the Electoral College meeting, meaning for Kentucky's 12 electors could vote for the candidate of their choice: eight voted for Indiana Senator Thomas Hendricks, while four voted for Greeley's running mate, Benjamin Gratz Brown.[1]

This is the last time a Republican won two terms without ever carrying the state.

Notes and References

  1. Web site: American presidential election, 1872. Encyclopædia Britannica. 5 December 2017.