1869 Vermont gubernatorial election explained

Election Name:1869 Vermont gubernatorial election
Country:Vermont
Flag Year:1837
Type:presidential
Ongoing:no
Previous Election:1868 Vermont gubernatorial election
Previous Year:1868
Next Election:1870 Vermont gubernatorial election
Next Year:1870
Candidate1:Peter T. Washburn
Party1:Republican Party (United States)
Popular Vote1:31,834
Percentage1:73.5%
Party2:Democratic Party (United States)
Candidate2:Homer W. Heaton
Popular Vote2:11,455
Percentage2:26.4%
Governor
Before Election:John B. Page
Before Party:Republican Party (United States)
After Election:Peter T. Washburn
After Party:Republican Party (United States)

The 1869 Vermont gubernatorial election took place on September 7, 1869. Incumbent Republican John B. Page, per the "Mountain Rule",[1] did not run for re-election to another term as Governor of Vermont. Republican candidate Peter T. Washburn, who had served in the Vermont House of Representatives and as Adjutant General of the Vermont Militia, defeated Democratic candidate Homer W. Heaton, a former member of the Vermont House, to succeed him. The 1869 election was the final time the Governor of Vermont was elected for a one-year term; terms were changed to two years beginning in 1870.

Notes and References

  1. Web site: Hand. Samuel B.. Mountain Rule Revisited. Vermont Historical Society. 4 October 2015.