1869 Iowa gubernatorial election explained

Election Name:1869 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1867 Iowa gubernatorial election
Previous Year:1867
Next Election:1871 Iowa gubernatorial election
Next Year:1871
Election Date:October 12, 1869
Nominee1:Samuel Merrill
Party1:Republican Party (United States)
Popular Vote1:97,243
Percentage1:62.93%
Nominee2:George Gillespie
Party2:Democratic Party (United States)
Popular Vote2:57,287
Percentage2:37.07%
Map Size:240px
Governor
Before Election:Samuel Merrill
Before Party:Republican Party (United States)
After Election:Samuel Merrill
After Party:Republican Party (United States)

The 1869 Iowa gubernatorial election was held on October 12, 1869. Incumbent Republican Samuel Merrill defeated Democratic nominee George Gillespie with 62.93% of the vote.

General election

Candidates