1868 United States presidential election in Nebraska explained

See main article: 1868 United States presidential election.

Election Name:1868 United States presidential election in Nebraska
Country:Nebraska
Type:presidential
Ongoing:no
Next Election:1872 United States presidential election in Nebraska
Next Year:1872
Election Date:November 3, 1868
Image1:Ulysses S Grant by Brady c1870-restored (3x4 crop).jpg
Nominee1:Ulysses S. Grant
Party1:Republican Party (United States)
Home State1:Illinois
Running Mate1:Schuyler Colfax
Electoral Vote1:3
Popular Vote1:9,772
Percentage1:63.91%
Nominee2:Horatio Seymour
Party2:Democratic Party (United States)
Home State2:New York
Running Mate2:Francis Preston Blair, Jr.
Electoral Vote2:0
Popular Vote2:5,519
Percentage2:36.09%
President
Before Election:Andrew Johnson
Before Party:Democratic Party (United States)
After Election:Ulysses S. Grant
After Party:Republican Party (United States)

The 1868 United States presidential election in Nebraska took place on November 3, 1868, as part of the 1868 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Nebraska participated in its first ever presidential election, having become the 37th state on March 1, 1867. The state was won by Ulysses S. Grant, formerly the 6th Commanding General of the United States Army (R-Illinois), running with Speaker of the House Schuyler Colfax, with 63.91% of the popular vote, against the 18th governor of New York, Horatio Seymour (DNew York), running with former Senator Francis Preston Blair, Jr., with 36.09% of the vote.[1]

See also

Notes and References

  1. Web site: 1868 Presidential Election Results Nebraska.