See main article: 1868 United States presidential election.
| Election Name: | 1868 United States presidential election in Louisiana |
| Country: | Louisiana |
| Flag Year: | 1861b |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1864 United States presidential election in Louisiana |
| Previous Year: | 1864 |
| Next Election: | 1872 United States presidential election in Louisiana |
| Next Year: | 1872 |
| Election Date: | November 3, 1868 |
| Image1: | Hon. Horatio Seymour, N.Y - NARA - 528568 (cropped).jpg |
| Nominee1: | Horatio Seymour |
| Party1: | Democratic Party (United States) |
| Home State1: | New York |
| Running Mate1: | Francis Preston Blair, Jr. |
| Electoral Vote1: | 7 |
| Popular Vote1: | 80,225 |
| Percentage1: | 70.69% |
| Nominee2: | Ulysses S. Grant |
| Party2: | Republican Party (United States) |
| Home State2: | Illinois |
| Running Mate2: | Schuyler Colfax |
| Electoral Vote2: | 0 |
| Popular Vote2: | 33,263 |
| Percentage2: | 29.31% |
| Map Size: | 350px |
| President | |
| Before Election: | Andrew Johnson |
| Before Party: | Democratic Party (United States) |
| After Election: | Ulysses S. Grant |
| After Party: | Republican Party (United States) |
The 1868 United States presidential election in Louisiana took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Louisiana voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won the state by a margin of 41.38%.
With 70.69% of the popular vote, Louisiana would be Seymour's second strongest victory in terms of percentage in the popular vote after Kentucky.[1]