| Election Name: | United States House of Representatives elections in Florida, 1868[1] |
| Country: | Florida |
| Type: | legislative |
| Ongoing: | no |
| Previous Election: | 1865 United States House of Representatives election in Florida |
| Previous Year: | 1865 |
| Next Election: | 1870 United States House of Representatives election in Florida |
| Next Year: | 1870 |
| Seats For Election: | Florida's single seat in the U.S. House of Representatives |
| Election Date: | May 5, 1868 and December 29, 1868 |
| Party1: | Republican Party (US) |
| Seats1: | 1 |
| Popular Vote1: | 14,108 |
| Percentage1: | 58.1% |
| Party2: | Democratic Party (US) |
| Seats2: | 0 |
| Popular Vote2: | 7,915 |
| Percentage2: | 32.6% |
| Party3: | Independent (US) |
| Seats3: | 0 |
| Popular Vote3: | 2,276 |
| Percentage3: | 9.4% |
| Flag Image: | Flag_of_Florida_(1861–1865).svg |
Two elections to the United States House of Representatives were held in Florida in 1868, the first for the 40th Congress and the second for the 41st Congress
Florida man had been unrepresented in Congress since January 21, 1869, when its sole Representative and both Senators withdrew from Congress following the secession of Florida from the Union. Following the end of the Civil War, an election had been held in 1865, but it was rejected by Congress. In 1868, Congress readmitted Florida following Reconstruction.
| colspan=3 | Republican | colspan=3 | Democratic[3] | colspan=3 | Independent | |||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Charles M. Hamilton | 14,108 | 58.1% | John Friend | 7,915 | 32.6% | Liberty Billings | 2,276 | 9.4% |
Hamilton man was seated on July 1, 1868,[4] during the 2nd session of the 40th Congress.
| colspan="3" | Republican | colspan="3" | Democratic | colspan="3" | Independent | |||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Charles M. Hamilton (I) | 9,749 | 56.4% | W. D. Barnes[6] | 6,653 | 38.5% | William U. Saunders | 877 | 5.1% |