| Election Name: | 1868 New Jersey gubernatorial election |
| Country: | New Jersey |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1865 New Jersey gubernatorial election |
| Previous Year: | 1865 |
| Next Election: | 1871 New Jersey gubernatorial election |
| Next Year: | 1871 |
| Election Date: | November 3, 1868 |
| Image1: | File:Theodore Fitz Randolph (cropped).jpg |
| Nominee1: | Theodore Fitz Randolph |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 83,955 |
| Percentage1: | 51.42% |
| Nominee2: | John Insley Blair |
| Party2: | Republican Party (United States) |
| Popular Vote2: | 79,333 |
| Percentage2: | 48.58% |
| Map Size: | 280px |
| Governor | |
| Before Election: | Marcus Lawrence Ward |
| Before Party: | Republican Party (United States) |
| After Election: | Theodore Fitz Randolph |
| After Party: | Democratic Party (United States) |
The 1868 New Jersey gubernatorial election was held on November 3, 1868. Democratic nominee Theodore Fitz Randolph defeated Republican nominee John Insley Blair with 51.42% of the vote.