| Election Name: | 1867 Iowa gubernatorial election |
| Country: | Iowa |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1865 Iowa gubernatorial election |
| Previous Year: | 1865 |
| Next Election: | 1869 Iowa gubernatorial election |
| Next Year: | 1869 |
| Election Date: | October 8, 1867 |
| Nominee1: | Samuel Merrill |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 90,204 |
| Percentage1: | 58.88% |
| Nominee2: | Charles Mason |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 62,966 |
| Percentage2: | 41.10% |
| Map Size: | 240px |
| Governor | |
| Before Election: | William M. Stone |
| Before Party: | Republican Party (United States) |
| After Election: | Samuel Merrill |
| After Party: | Republican Party (United States) |
The 1867 Iowa gubernatorial election was held on October 8, 1867. Republican nominee Samuel Merrill defeated Democratic nominee Charles Mason with 58.88% of the vote.