1866 New Hampshire gubernatorial election explained

Election Name:1866 New Hampshire gubernatorial election
Country:New Hampshire
Type:Presidential
Ongoing:no
Previous Election:1865 New Hampshire gubernatorial election
Previous Year:1865
Next Election:1867 New Hampshire gubernatorial election
Next Year:1867
Election Date:13 March 1866
Nominee1:Frederick Smyth
Party1:Republican Party (United States)
Popular Vote1:35,137
Percentage1:53.53%
Nominee2:John G. Sinclair
Party2:Democratic Party (United States)
Popular Vote2:30,481
Percentage2:46.44%
Map Size:245px
Governor
Before Election:Frederick Smyth
Before Party:Republican Party (United States)
After Election:Frederick Smyth
After Party:Republican Party (United States)

The 1866 New Hampshire gubernatorial election was held on 13 March 1866 in order to elect the Governor of New Hampshire. Incumbent Republican Governor Frederick Smyth won re-election against Democratic nominee John G. Sinclair.[1]

General election

On election day, 13 March 1866, incumbent Republican Governor Frederick Smyth won re-election by a margin of 4,656 votes against his opponent Democratic nominee John G. Sinclair, thereby retaining Republican control over the office of Governor. Smyth was sworn in for his second term on 5 June 1866.[2]

Results

Notes and References

  1. Web site: Frederick Smyth . 3 April 2024 . National Governors Association.
  2. Web site: NH Governor . ourcampaigns.com . 27 July 2005 . 3 April 2024.