| Election Name: | 1865 New Hampshire gubernatorial election |
| Country: | New Hampshire |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1864 New Hampshire gubernatorial election |
| Previous Year: | 1864 |
| Next Election: | 1866 New Hampshire gubernatorial election |
| Next Year: | 1866 |
| Election Date: | 14 March 1865 |
| Nominee1: | Frederick Smyth |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 34,145 |
| Percentage1: | 54.91% |
| Nominee2: | Edward W. Harrington |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 28,017 |
| Percentage2: | 45.06% |
| Map Size: | 245px |
| Governor | |
| Before Election: | Joseph A. Gilmore |
| Before Party: | Republican Party (United States) |
| After Election: | Frederick Smyth |
| After Party: | Republican Party (United States) |
The 1865 New Hampshire gubernatorial election was held on 14 March 1865 in order to elect the Governor of New Hampshire. Republican nominee and incumbent Mayor of Manchester Frederick Smyth defeated Democratic nominee and former Mayor of Manchester Edward W. Harrington.[1]
On election day, 14 March 1865, Republican nominee Frederick Smyth won the election by a margin of 6,128 votes against his opponent Democratic nominee Edward W. Harrington, thereby retaining Republican control over the office of Governor. Smyth was sworn in as the 30th Governor of New Hampshire on 7 June 1865.[2]