1863 United States Senate election in Massachusetts explained

Election Name:1863 United States Senate election in Massachusetts
Type:presidential
Ongoing:no
Previous Election:1857 United States Senate election in Massachusetts
Previous Year:1857
Next Election:1869 United States Senate election in Massachusetts
Next Year:1869
Election Date:January 15, 1863
Votes For Election:40 Members of the Massachusetts Senate
235 Members of the Massachusetts House
Majority vote of each house needed to win
1Blank:Senate
2Blank:Percentage
3Blank:House
4Blank:Percentage
Image1:Charles Sumner - Brady-Handy.jpg
Nominee1:Charles Sumner
Party1:Republican Party (United States)
1Data1:33
2Data1:82.5%
3Data1:194
4Data1:82.55%
Nominee2:Josiah Abbott
Party2:Democratic Party (United States)
1Data2:5
2Data2:12.5%
3Data2:38
4Data2:16.17%
Senator
Before Election:Charles Sumner
Before Party:Republican Party (United States)
After Election:Charles Sumner
After Party:Republican Party (United States)

The 1863 United States Senate election in Massachusetts was held on January 9, 1863. Incumbent Charles Sumner was re-elected to a third term in office.

At the time, Massachusetts elected United States senators by a majority vote of each separate house of the Massachusetts General Court: the House and the Senate.

Background

In the 1862 state legislative elections, supporters of the Lincoln administration who nonetheless opposed the emancipation of Southern slaves and Senator Sumner's re-election organized a "People's Convention," hoping to consolidate opposition and gain enough seats in the legislature to deny Sumner election. However, the legislature remained largely Republican, ensuring Sumner's victory in the January election.[1]

Senate

The lone vote for Adams was cast by Senator Whitney of Hampden. Senator Crane of Worcester County did not vote.

Notes and References

  1. News: THE ELECTIONS. . Philadelphia Saturday Evening Post . 15 Nov 1862.