| Election Name: | 1863 Iowa gubernatorial election |
| Country: | Iowa |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1861 Iowa gubernatorial election |
| Previous Year: | 1861 |
| Next Election: | 1865 Iowa gubernatorial election |
| Next Year: | 1865 |
| Election Date: | 13 October 1863 |
| Nominee1: | William M. Stone |
| Party1: | Republican Party (United States) |
| Popular Vote1: | 86,118 |
| Percentage1: | 60.51% |
| Nominee2: | James M. Tuttle |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 56,169 |
| Percentage2: | 39.47% |
| Governor | |
| Before Election: | Samuel J. Kirkwood |
| Before Party: | Republican Party (United States) |
| After Election: | William M. Stone |
| After Party: | Republican Party (United States) |
The 1863 Iowa gubernatorial election was held on 13 October 1863 in order to elect the Governor of Iowa. Republican nominee William M. Stone defeated Democratic nominee James M. Tuttle.[1]
On election day, 13 October 1863, Republican nominee William M. Stone won the election by a margin of 29,949 votes against his opponent Democratic nominee James M. Tuttle, thereby holding Republican control over the office of Governor. Stone was sworn in as the 6th Governor of Iowa on 14 January 1864.[2]