1861 Iowa gubernatorial election explained

Election Name:1861 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1859 Iowa gubernatorial election
Previous Year:1859
Next Election:1863 Iowa gubernatorial election
Next Year:1863
Election Date:8 October 1861
Nominee1:Samuel J. Kirkwood
Party1:Republican Party (United States)
Popular Vote1:60,303
Percentage1:55.48%
Nominee2:William H. Merritt
Party2:Democratic Party (United States)
Popular Vote2:43,245
Percentage2:39.78%
Map Size:240px
Governor
Before Election:Samuel J. Kirkwood
Before Party:Republican Party (United States)
After Election:Samuel J. Kirkwood
After Party:Republican Party (United States)

The 1861 Iowa gubernatorial election was held on 8 October 1861 in order to elect the Governor of Iowa. Incumbent Republican Governor Samuel J. Kirkwood was re-elected against Democratic nominee William H. Merritt and several other candidates.[1]

General election

On election day, 8 October 1861, incumbent Republican Governor Samuel J. Kirkwood won re-election by a margin of 17,058 votes against his foremost opponent Democratic nominee William H. Merritt, thereby holding Republican control over the office of Governor. Kirkwood was sworn in for his second term on 3 January 1862.[2]

Results

Notes and References

  1. Web site: Samuel Jordan Kirkwood . 28 November 2023 . National Governors Association.
  2. Web site: IA Governor . ourcampaigns.com . 5 July 2008 . 28 November 2023.