1860 Missouri gubernatorial election explained

Election Name:1860 Missouri gubernatorial election
Type:presidential
Ongoing:no
Previous Election:1857 Missouri gubernatorial special election
Previous Year:1857(special)
Next Election:1864 Missouri gubernatorial election
Next Year:1864
Election Date:August 6, 1860
Nominee1:Claiborne Fox Jackson
Party1:Democratic Party (United States)
Popular Vote1:74,446
Percentage1:46.95%
Nominee2:Sample Orr
Party2:Constitutional Union Party (United States)
Popular Vote2:66,583
Percentage2:41.99%
Nominee3:Hancock Lee Jackson
Party3:Southern Democratic (United States)
Popular Vote3:11,415
Percentage3:7.20%
Map Size:270px
Governor
Before Election:Robert Marcellus Stewart
Before Party:Democratic Party (United States)
After Election:Claiborne Fox Jackson
After Party:Democratic Party (United States)

The 1860 Missouri gubernatorial election was held on August 6, 1860, and resulted in a victory for the Democratic nominee, Claiborne Fox Jackson. Jackson defeated the nominee of the Constitutional Union Party, Sample Orr, and Southern "Brekenridge" Democrat Former Gov. Hancock Lee Jackson to become the fifteenth governor of Missouri. Republican James B. Gardenhire also ran in the election, but received a negligible number of votes.

Before the next election in 1864, three men would serve as Governor of Missouri: first, Claiborne Fox Jackson until his defection to the Confederacy in July 1861, then Hamilton Rowan Gamble until his death in January 1864, and finally Lt. Gov Willard Preble Hall.[1]

Notes and References

  1. Web site: SOS, Missouri – State Archives: Governors . Sos.mo.gov . 2013-03-22.