1859 Iowa gubernatorial election explained

Election Name:1859 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1857 Iowa gubernatorial election
Previous Year:1857
Next Election:1861 Iowa gubernatorial election
Next Year:1861
Election Date:11 October 1859
Nominee1:Samuel J. Kirkwood
Party1:Republican Party (United States)
Popular Vote1:56,532
Percentage1:51.46%
Nominee2:Augustus C. Dodge
Party2:Democratic Party (United States)
Popular Vote2:53,332
Percentage2:48.54%
Map Size:240px
Governor
Before Election:Ralph P. Lowe
Before Party:Republican Party (United States)
After Election:Samuel J. Kirkwood
After Party:Republican Party (United States)

The 1859 Iowa gubernatorial election was held on 11 October 1859 in order to elect the Governor of Iowa. Republican nominee and incumbent Iowa Senate member Samuel J. Kirkwood defeated Democratic nominee and former United States Ambassador to Spain Augustus C. Dodge.[1]

General election

On election day, 11 October 1859, Republican nominee Samuel J. Kirkwood won the election by a margin of 3,200 votes against his opponent Democratic nominee Augustus C. Dodge, thereby holding Republican control over the office of Governor. Kirkwood was sworn in as the 5th Governor of Iowa on 11 January 1860.[2]

Results

Notes and References

  1. Web site: Samuel Jordan Kirkwood . 27 November 2023 . National Governors Association.
  2. Web site: IA Governor . ourcampaigns.com . 4 March 2005 . 27 November 2023.