1856 United States presidential election in North Carolina explained

See main article: 1856 United States presidential election.

Election Name:1856 United States presidential election in North Carolina
Country:North Carolina
Flag Year:1856
Type:presidential
Ongoing:no
Previous Election:1852 United States presidential election in North Carolina
Previous Year:1852
Next Election:1860 United States presidential election in North Carolina
Next Year:1860
Election Date:November 4, 1856
Image1:James Buchanan (cropped).jpg
Nominee1:James Buchanan
Party1:Democratic Party (United States)
Home State1:Pennsylvania
Running Mate1:John C. Breckinridge
Electoral Vote1:10
Popular Vote1:48,243
Percentage1:56.78%
Nominee2:Millard Fillmore
Party2:Whig Party (United States)
Home State2:New York
Running Mate2:Andrew J. Donelson
Electoral Vote2:0
Popular Vote2:36,720
Percentage2:43.22%
Map Size:380px
President
Before Election:Franklin Pierce
Before Party:Democratic Party (United States)
After Election:James Buchanan
After Party:Democratic Party (United States)

The 1856 United States presidential election in North Carolina took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

North Carolina voted for the Democratic candidate, James Buchanan, over Whig candidate Millard Fillmore. Fillmore ran under the American Party ticket in most states, but ran as a Whig in North Carolina after receiving the endorsement of the party at the 1856 Whig National Convention.[1] Buchanan won North Carolina by a margin of 13.56%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Notes and References

  1. Web site: Whig Party Platform of 1856. The American Presidency Project. University of California Santa Barbara. 3 December 2017.