1856 United States presidential election in Kentucky explained

See main article: 1856 United States presidential election.

Election Name:1856 United States presidential election in Kentucky
Flag Year:1856
Type:presidential
Ongoing:no
Previous Election:1852 United States presidential election in Kentucky
Previous Year:1852
Next Election:1860 United States presidential election in Kentucky
Next Year:1860
Election Date:November 4, 1856
Image1:James Buchanan (cropped).jpg
Nominee1:James Buchanan
Party1:Democratic Party (United States)
Home State1:Pennsylvania
Running Mate1:John C. Breckinridge
Electoral Vote1:12
Popular Vote1:74,642
Percentage1:52.54%
Nominee2:Millard Fillmore
Party2:Know Nothing
Home State2:New York
Running Mate2:Andrew J. Donelson
Electoral Vote2:0
Popular Vote2:67,416
Percentage2:47.46%
Map Size:380px
President
Before Election:Franklin Pierce
Before Party:Democratic Party (United States)
After Election:James Buchanan
After Party:Democratic Party (United States)

The 1856 United States presidential election in Kentucky took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.

Kentucky voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Kentucky by a margin of 5.08%.

Republican Party candidate John C. Frémont was not on the ballot in the state.