1856 United States presidential election in Indiana explained

See main article: 1856 United States presidential election.

Country:Indiana
Flag Year:1856
Type:presidential
Ongoing:no
Previous Election:1852 United States presidential election in Indiana
Previous Year:1852
Next Election:1860 United States presidential election in Indiana
Next Year:1860
Election Date:November 4, 1856
Image1:James Buchanan (cropped).jpg
Nominee1:James Buchanan
Party1:Democratic Party (United States)
Home State1:Pennsylvania
Running Mate1:John C. Breckinridge
Electoral Vote1:13
Popular Vote1:118,670
Percentage1:50.41%
Nominee2:John C. Frémont
Party2:Republican Party (United States)
Home State2:California
Running Mate2:William L. Dayton
Electoral Vote2:0
Popular Vote2:94,375
Percentage2:40.09%
Image3:Fillmore (cropped).jpg
Nominee3:Millard Fillmore
Party3:Know Nothing
Home State3:New York
Running Mate3:Andrew J. Donelson
Electoral Vote3:0
Popular Vote3:22,386
Percentage3:9.51%
Map Size:300px
President
Before Election:Franklin Pierce
Before Party:Democratic Party (United States)
After Election:James Buchanan
After Party:Democratic Party (United States)

The 1856 United States presidential election in Indiana took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Indiana voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Indiana by a margin of 10.32 percentage points.

A Democratic presidential nominee would not win Indiana again until Samuel J. Tilden narrowly won it in 1876.

See also