1856 United States presidential election in Delaware explained

See main article: 1856 United States presidential election.

Election Name:1856 United States presidential election in Delaware
Country:Delaware
Type:presidential
Ongoing:no
Previous Election:1852 United States presidential election in Delaware
Previous Year:1852
Next Election:1860 United States presidential election in Delaware
Next Year:1860
Election Date:November 4, 1856
Image1:James Buchanan.jpg
Nominee1:James Buchanan
Party1:Democratic Party (United States)
Home State1:Pennsylvania
Running Mate1:John C. Breckinridge
Electoral Vote1:3
Popular Vote1:8,004
Percentage1:54.83%
Nominee2:Millard Fillmore
Party2:Know Nothing
Home State2:New York
Running Mate2:Andrew Jackson Donelson
Electoral Vote2:0
Popular Vote2:6,275
Percentage2:42.99%
Map Size:210px
President
Before Election:Franklin Pierce
Before Party:Democratic Party (United States)
After Election:James Buchanan
After Party:Democratic

The 1856 United States presidential election in Delaware took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Democratic candidate, James Buchanan, over the Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore.

Buchanan won the state by a margin of 11.84%.

See also