See main article: 1856 United States presidential election.
Election Name: | 1856 United States presidential election in Alabama |
Country: | Alabama |
Type: | presidential |
Ongoing: | no |
Previous Election: | 1852 United States presidential election in Alabama |
Previous Year: | 1852 |
Election Date: | November 4, 1856 |
Next Election: | 1860 United States presidential election in Alabama |
Next Year: | 1860 |
Image1: | James Buchanan (cropped).jpg |
Nominee1: | James Buchanan |
Party1: | Democratic Party (United States) |
Home State1: | Pennsylvania |
Electoral Vote1: | 9 |
Popular Vote1: | 46,739 |
Percentage1: | 62.08% |
President | |
Before Election: | Franklin Pierce |
Before Party: | Democratic Party (United States) |
After Election: | James Buchanan |
After Party: | Democratic Party (United States) |
Nominee2: | Millard Fillmore |
Party2: | Know Nothing |
Home State2: | New York |
Running Mate2: | Andrew J. Donelson |
Electoral Vote2: | 0 |
Popular Vote2: | 28,552 |
Percentage2: | 37.92% |
Map Size: | 200px |
The 1856 United States presidential election in Alabama was held on November 4, 1856. Alabama voters chose 9 electors to represent the state in the Electoral College, which chose the president and vice president.
Alabama was won by Senator James Buchanan (D–Pennsylvania), running with Representative and future presidential candidate in the 1860 presidential election John C. Breckinridge, with 62.08% of the popular vote, against the 13th president of the United States Millard Fillmore (A–New York), running with the 2nd United States Ambassador to Germany Andrew Jackson Donelson, with 37.92% of the popular vote.[1]
The Republican Party nominee John C. Frémont was not on the ballot.