1856 United States presidential election in Alabama explained

See main article: 1856 United States presidential election.

Election Name:1856 United States presidential election in Alabama
Country:Alabama
Type:presidential
Ongoing:no
Previous Election:1852 United States presidential election in Alabama
Previous Year:1852
Election Date:November 4, 1856
Next Election:1860 United States presidential election in Alabama
Next Year:1860
Image1:James Buchanan (cropped).jpg
Nominee1:James Buchanan
Party1:Democratic Party (United States)
Home State1:Pennsylvania
Electoral Vote1:9
Popular Vote1:46,739
Percentage1:62.08%
President
Before Election:Franklin Pierce
Before Party:Democratic Party (United States)
After Election:James Buchanan
After Party:Democratic Party (United States)
Nominee2:Millard Fillmore
Party2:Know Nothing
Home State2:New York
Running Mate2:Andrew J. Donelson
Electoral Vote2:0
Popular Vote2:28,552
Percentage2:37.92%
Map Size:200px

The 1856 United States presidential election in Alabama was held on November 4, 1856. Alabama voters chose 9 electors to represent the state in the Electoral College, which chose the president and vice president.

Alabama was won by Senator James Buchanan (DPennsylvania), running with Representative and future presidential candidate in the 1860 presidential election John C. Breckinridge, with 62.08% of the popular vote, against the 13th president of the United States Millard Fillmore (ANew York), running with the 2nd United States Ambassador to Germany Andrew Jackson Donelson, with 37.92% of the popular vote.[1]

The Republican Party nominee John C. Frémont was not on the ballot.

See also

Notes and References

  1. Web site: 1856 Presidential Election Results Alabama.