1856 Rhode Island gubernatorial election explained

Election Name:1856 Rhode Island gubernatorial election
Type:Presidential
Ongoing:no
Previous Election:1855 Rhode Island gubernatorial election
Previous Year:1855
Next Election:1857 Rhode Island gubernatorial election
Next Year:1857
Election Date:2 April 1856
Nominee1:William W. Hoppin
Party1:Republican Party (United States)
Popular Vote1:9,865
Percentage1:57.95%
Nominee2:Americus V. Potter
Party2:Democratic Party (United States)
Popular Vote2:7,131
Percentage2:41.89%
Map Size:200px
Governor
Before Election:William W. Hoppin
Before Party:Republican Party (United States)
After Election:William W. Hoppin
After Party:Republican Party (United States)

The 1856 Rhode Island gubernatorial election was held on 2 April 1856 in order to elect the Governor of Rhode Island. Incumbent Republican Governor William W. Hoppin won re-election against Democratic nominee Americus V. Potter in a rematch from the 1855 Rhode Island gubernatorial election.[1]

General election

Incumbent Whig Governor William W. Hoppin had changed parties before the election and had instead joined the Republican party, by being the incumbent Governor, Hoppin's quickly became the Republican nominee for re-election. On election day, 2 April 1856, incumbent Republican Governor William W. Hoppin won re-election by a margin of 2,734 votes against his Democratic opponent Americus V. Potter, thereby retaining Republican control over the office of Governor. Hoppin was sworn in for his third term on 26 May 1856.[2]

Results

Notes and References

  1. Book: McLoughlin. William G. Rhode Island: A History. 1986. W.W. Norton & Company. New York. 0-393-30271-7. 141–142.
  2. Web site: RI Governor . ourcampaigns.com . 6 June 2005 . 10 May 2023.