1855 United States Senate election in Wisconsin explained

Election Name:1855 United States Senate election in Wisconsin
Country:Wisconsin
Type:presidential
Ongoing:no
Previous Election:1849 United States Senate election in Wisconsin
Previous Year:1849
Next Election:1861 United States Senate election in Wisconsin
Next Year:1861
Election Date:January 30, 1855February 1, 1855
Vote Type:Legislative
Image1:Charles Durkee portrait.jpg
Nominee1:Charles Durkee
Party1:Republican Party (United States)
Popular Vote1:54
Percentage1:50.47%
Nominee2:Byron Kilbourn
Party2:Democratic Party (United States)
Popular Vote2:39
Percentage2:36.45%
Nominee3:Others
Popular Vote3:14
Percentage3:13.08%
U.S. Senator
Before Election:Isaac P. Walker
Before Party:Democratic Party (United States)
After Election:Charles Durkee
After Party:Republican Party (United States)

The 1855 United States Senate election in Wisconsin was held in the 8th Wisconsin Legislature between, and Incumbent Democratic U.S. senator Isaac P. Walker did not run for re-election. Former U.S. representative Charles Durkee was elected United States senator on the eighth ballot, and became the first Republican U.S. senator from Wisconsin.[1]

This was the first U.S. Senate election in Wisconsin after the creation of the Republican Party. Republicans held a majority in the Wisconsin State Assembly, with 44 of 82 seats; Democrats held a narrow majority in the Wisconsin Senate, with 13 of 25 seats. As the Republican Party was a new creation, party loyalties were still in flux, with several members of the legislature not officially aligned with either major party.

With 44 seats in the Assembly and 11 seats in the Senate, Republicans technically held a bare majority of the total legislator votes, but they struggled for three days to unify behind their candidate. Durkee ultimately received 53 of the 55 votes of Republican legislators. The two holdouts who did not vote for Durkee were representatives Joseph Schrage of Sheboygan County and Mitchell L. Delaney of Washington County. To secure the necessary 54 votes, Durkee won the vote of independent (later Republican) Alexander Randall.[1]

Major candidates

Democratic

Republican

Results

Votes on January 30, 1855

The legislature met in joint session on January 30 and took three votes in succession to try to pick a U.S. senator.

No person securing the majority, the convention voted to adjourn until 11am the following day.

Votes on January 31, 1855

The legislature re-convened in joint session on Wednesday, January 31, and took three more votes for U.S. senator.

No person securing the majority, the convention voted to adjourn until 3pm the following day.

Votes on February 1, 1855

The legislature re-convened in joint session on Thursday, February 1, and took two more votes for U.S. senator, finally achieving a majority on the 2nd vote of the day, the 8th ballot overall.

Charles Durkee, having received a majority of the 107 votes of the legislature, was declared elected U.S. senator.

See also

Notes and References

  1. Journal of the Senate of Wisconsin . 1855 . . 120–152 . November 26, 2024 .