1855 Rhode Island gubernatorial election explained

Election Name:1855 Rhode Island gubernatorial election
Type:Presidential
Ongoing:no
Previous Election:1854 Rhode Island gubernatorial election
Previous Year:1854
Next Election:1856 Rhode Island gubernatorial election
Next Year:1856
Election Date:4 April 1855
Nominee1:William W. Hoppin
Party1:Whig Party (United States)
Popular Vote1:11,130
Percentage1:79.97%
Nominee2:Americus V. Potter
Party2:Democratic Party (United States)
Popular Vote2:2,729
Percentage2:19.61%
Map Size:200px
Governor
Before Election:William W. Hoppin
Before Party:Whig Party (United States)
After Election:William W. Hoppin
After Party:Whig Party (United States)

The 1855 Rhode Island gubernatorial election was held on 4 April 1855 in order to elect the Governor of Rhode Island. Incumbent Whig Governor William W. Hoppin won re-election against Democratic nominee Americus V. Potter.[1]

General election

On election day, 4 April 1855, incumbent Whig Governor William W. Hoppin won re-election by a margin of 8,401 votes against his Democratic opponent Americus V. Potter, thereby retaining Whig control over the office of Governor. Hoppin was sworn in for his second term on 26 May 1855.[2]

Results

Notes and References

  1. Book: McLoughlin. William G. Rhode Island: A History. 1986. W.W. Norton & Company. New York. 0-393-30271-7. 141–142.
  2. Web site: RI Governor . ourcampaigns.com . 6 June 2005 . 10 May 2023.