1854 Rhode Island gubernatorial election explained

Election Name:1854 Rhode Island gubernatorial election
Type:Presidential
Ongoing:no
Previous Election:1853 Rhode Island gubernatorial election
Previous Year:1853
Next Election:1855 Rhode Island gubernatorial election
Next Year:1855
Election Date:5 April 1854
Nominee1:William W. Hoppin
Party1:Whig Party (United States)
Popular Vote1:9,216
Percentage1:57.76%
Nominee2:Francis M. Dimond
Party2:Democratic Party (United States)
Popular Vote2:6,523
Percentage2:40.88%
Map Size:200px
Governor
Before Election:Francis M. Dimond
Before Party:Democratic Party (United States)
After Election:William W. Hoppin
After Party:Whig Party (United States)

The 1854 Rhode Island gubernatorial election was held on 5 April 1854 in order to elect the Governor of Rhode Island. Incumbent Democratic Governor Francis M. Dimond was defeated by Whig nominee William W. Hoppin.

General election

Following the resignation of Governor Philip Allen in order to become a United States Senator on 20 July 1853, Lieutenant Governor Francis M. Dimond succeeded him and became the democratic nominee in the 1854 gubernatorial election so he could be elected to a full term. Meanwhile, the Whig party again nominated William W. Hoppin, who had sought the governorship before during the gubernatorial election of 1853, but had lost to incumbent Governor Philip Allen. On election day, 5 April 1854, incumbent Democratic Governor Francis M. Dimond was defeated by a margin of 2,693 votes against his Whig opponent William W. Hoppin, thereby losing democratic control over the office of Governor to the Whig party. Hoppin was sworn in as the 24th Governor of Rhode Island on 2 May 1854.[1]

Results

Notes and References

  1. Web site: RI Governor . ourcampaigns.com . 6 June 2005 . 10 May 2023.