1854 Iowa gubernatorial election explained

Election Name:1854 Iowa gubernatorial election
Country:Iowa
Type:Presidential
Ongoing:no
Previous Election:1850 Iowa gubernatorial election
Previous Year:1850
Next Election:1857 Iowa gubernatorial election
Next Year:1857
Election Date:7 August 1854
Nominee1:James W. Grimes
Party1:Whig Party (United States)
Popular Vote1:23,312
Percentage1:52.38%
Nominee2:Curtis Bates
Party2:Democratic Party (United States)
Popular Vote2:21,192
Percentage2:47.62%
Map Size:250px
Governor
Before Election:Stephen P. Hempstead
Before Party:Democratic Party (United States)
After Election:James W. Grimes
After Party:Whig Party (United States)

The 1854 Iowa gubernatorial election was held on 7 August 1854 in order to elect the Governor of Iowa. Whig nominee James W. Grimes defeated Democratic nominee Curtis Bates.[1]

General election

On election day, 7 August 1854, Whig nominee James W. Grimes won the election by a margin of 2,120 votes against his opponent Democratic nominee Curtis Bates, thereby gaining Whig control over the office of Governor. Grimes was sworn in as the 3rd Governor of Iowa on 9 December 1854.[2]

Results

Notes and References

  1. Web site: James Wilson Grimes . 27 November 2023 . National Governors Association.
  2. Web site: IA - Governor . ourcampaigns.com . 4 March 2005 . 27 November 2023.