| Election Name: | 1854 Iowa gubernatorial election |
| Country: | Iowa |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1850 Iowa gubernatorial election |
| Previous Year: | 1850 |
| Next Election: | 1857 Iowa gubernatorial election |
| Next Year: | 1857 |
| Election Date: | 7 August 1854 |
| Nominee1: | James W. Grimes |
| Party1: | Whig Party (United States) |
| Popular Vote1: | 23,312 |
| Percentage1: | 52.38% |
| Nominee2: | Curtis Bates |
| Party2: | Democratic Party (United States) |
| Popular Vote2: | 21,192 |
| Percentage2: | 47.62% |
| Map Size: | 250px |
| Governor | |
| Before Election: | Stephen P. Hempstead |
| Before Party: | Democratic Party (United States) |
| After Election: | James W. Grimes |
| After Party: | Whig Party (United States) |
The 1854 Iowa gubernatorial election was held on 7 August 1854 in order to elect the Governor of Iowa. Whig nominee James W. Grimes defeated Democratic nominee Curtis Bates.[1]
On election day, 7 August 1854, Whig nominee James W. Grimes won the election by a margin of 2,120 votes against his opponent Democratic nominee Curtis Bates, thereby gaining Whig control over the office of Governor. Grimes was sworn in as the 3rd Governor of Iowa on 9 December 1854.[2]