1852 United States presidential election in Virginia explained

See main article: 1852 United States presidential election.

Election Name:1852 United States presidential election in Virginia
Country:Virginia
Flag Year:1788
Type:presidential
Ongoing:no
Previous Election:1848 United States presidential election in Virginia
Previous Year:1848
Next Election:1856 United States presidential election in Virginia
Next Year:1856
Election Date:November 2, 1852
Image1:Mathew Brady - Franklin Pierce (cropped).jpg
Nominee1:Franklin Pierce
Party1:Democratic Party (United States)
Home State1:New Hampshire
Running Mate1:William R. King
Electoral Vote1:15
Popular Vote1:73,872
Percentage1:55.71%
Nominee2:Winfield Scott
Party2:Whig Party (United States)
Home State2:New Jersey
Running Mate2:William A. Graham
Electoral Vote2:0
Popular Vote2:58,732
Percentage2:44.29%
Map Size:435px
President
Before Election:Millard Fillmore
Before Party:Whig Party (United States)
After Election:Franklin Pierce
After Party:Democratic Party (United States)

The 1852 United States presidential election in Virginia took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Virginia voted for the Democratic candidate, former U.S. Senator Franklin Pierce over the Whig candidate, military lieutenant general Winfield Scott. Pierce won the state by a margin of 11.42%.

Results

United States presidential election in Virginia, 1852[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticFranklin Pierce73,87255.71%15
WhigWinfield Scott58,73244.29%0
Totals132,604100.0%15

Notes and References

  1. Web site: 1852 Presidential General Election Results - Virginia. U.S. Election Atlas. 12 April 2013.