1852 United States presidential election in Texas explained

See main article: 1852 United States presidential election.

Election Name:1852 United States presidential election in Texas
Country:Texas
Type:presidential
Ongoing:no
Previous Election:1848 United States presidential election in Texas
Previous Year:1848
Election Date:November 2, 1852
Next Election:1856 United States presidential election in Texas
Next Year:1856
Image1:Mathew Brady - Franklin Pierce (cropped).jpg
Nominee1:Franklin Pierce
Party1:Democratic Party (United States)
Home State1:New Hampshire
Running Mate1:William R. King
Electoral Vote1:4
Popular Vote1:13,552
Percentage1:73.07%
Nominee2:Winfield Scott
Party2:Whig Party (United States)
Home State2:New Jersey
Running Mate2:William A. Graham
Electoral Vote2:0
Popular Vote2:4,995
Percentage2:26.93%
Map Size:350px
President
Before Election:Millard Fillmore
Before Party:Whig Party (United States)
After Election:Franklin Pierce
After Party:Democratic Party (United States)

The 1852 United States presidential election in Texas was held on November 2, 1852, as part of the 1852 United States presidential election. State voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

Texas voted for the Democratic nominee Franklin Pierce, who received 73.068% of Texas's votes. Texas was Pierce's strongest state by about 9% (Georgia was 2nd with 62.7% of the vote from the state). This Election and 1932 are the only 2 elections where a candidate won ever county in the state of Texas.

Results

1852 United States presidential election in Texas[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticFranklin Pierce13,552 73.068%4
WhigWinfield Scott4,99526.932%0
Total18,547100.0%4

See also

Notes and References

  1. Web site: David Leip's Atlas of U.S. Presidential Elections.