1852 United States presidential election in Tennessee explained

See main article: 1852 United States presidential election.

Election Name:1852 United States presidential election in Tennessee
Type:presidential
Ongoing:no
Previous Election:1848 United States presidential election in Tennessee
Previous Year:1848
Next Election:1856 United States presidential election in Tennessee
Next Year:1856
Election Date:November 2, 1852
Image1:Winfield Scott by Fredricks, 1862 (cropped).jpg
Nominee1:Winfield Scott
Party1:Whig Party (United States)
Home State1:New Jersey
Running Mate1:William A. Graham
Electoral Vote1:12
Popular Vote1:58,586
Percentage1:50.73%
Nominee2:Franklin Pierce
Party2:Democratic Party (United States)
Home State2:New Hampshire
Running Mate2:William R. King
Electoral Vote2:0
Popular Vote2:56,900
Percentage2:49.27%
Map Size:350px
President
Before Election:Millard Fillmore
Before Party:Whig Party (United States)
After Election:Franklin Pierce
After Party:Democratic Party (United States)

The 1852 United States presidential election in Tennessee took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Whig candidate, Winfield Scott, over Democratic candidate Franklin Pierce.

Tennessee was one of the four states to vote for Scott in the 1852 election with the other three being Kentucky, Massachusetts and Vermont.

Despite Scott winning the state by a narrow margin of 1.46%, Tennessee would prove to be Scott's second strongest state in the nation after Kentucky.[1]

Notes and References

  1. Web site: 1852 Presidential Election Statistics. Dave Leip’s Atlas of U.S. Presidential Elections. 2018-03-05.