See main article: 1852 United States presidential election.
| Election Name: | 1852 United States presidential election in Rhode Island |
| Country: | Rhode Island |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1848 United States presidential election in Rhode Island |
| Previous Year: | 1848 |
| Next Election: | 1856 United States presidential election in Rhode Island |
| Next Year: | 1856 |
| Election Date: | November 2, 1852 |
| Image1: | Mathew Brady - Franklin Pierce (cropped).jpg |
| Nominee1: | Franklin Pierce |
| Party1: | Democratic Party (United States) |
| Home State1: | New Hampshire |
| Running Mate1: | William R. King |
| Electoral Vote1: | 4 |
| Popular Vote1: | 8,735 |
| Percentage1: | 51.37% |
| Nominee2: | Winfield Scott |
| Party2: | Whig Party (United States) |
| Home State2: | New Jersey |
| Running Mate2: | William Alexander Graham |
| Electoral Vote2: | 0 |
| Popular Vote2: | 7,626 |
| Percentage2: | 44.85% |
| Map Size: | 250px |
| President | |
| Before Election: | Millard Fillmore |
| Before Party: | Whig Party (United States) |
| After Election: | Franklin Pierce |
| After Party: | Democratic Party (United States) |
The 1852 United States presidential election in Rhode Island took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 6.52%. This was the first of three times that the state voted differently than Massachusetts (along with 1972 and 1980).
This would be the final time until 1912 that a Democratic presidential candidate was able to win Rhode Island and the final time until 1928 that a Democratic candidate won a majority of the popular vote.