1852 United States presidential election in New Jersey explained

See main article: 1852 United States presidential election.

Election Name:1852 United States presidential election in New Jersey
Country:New Jersey
Type:presidential
Ongoing:no
Previous Election:1848 United States presidential election in New Jersey
Previous Year:1848
Next Election:1856 United States presidential election in New Jersey
Next Year:1856
Election Date:November 2, 1852
Image1:Mathew Brady - Franklin Pierce (cropped).jpg
Nominee1:Franklin Pierce
Party1:Democratic Party (United States)
Home State1:New Hampshire
Running Mate1:William R. King
Electoral Vote1:7
Popular Vote1:44,305
Percentage1:53.24%
Nominee2:Winfield Scott
Party2:Whig Party (United States)
Home State2:New Jersey
Running Mate2:William A. Graham
Electoral Vote2:0
Popular Vote2:38,556
Percentage2:44.97%
Map Size:350px
President
Before Election:Millard Fillmore
Before Party:Whig Party (United States)
After Election:Franklin Pierce
After Party:Democratic Party (United States)

The 1852 United States presidential election in New Jersey took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 6.91%, making him the first Democratic presidential candidate since Andrew Jackson in 1832 to win the state. This is the last time that a Democrat won without carrying Middlesex County.

See also