See main article: 1852 United States presidential election.
| Election Name: | 1852 United States presidential election in Missouri |
| Country: | Missouri |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1848 United States presidential election in Missouri |
| Previous Year: | 1848 |
| Next Election: | 1856 United States presidential election in Missouri |
| Next Year: | 1856 |
| Election Date: | November 2, 1852 |
| Image1: | Mathew Brady - Franklin Pierce (cropped).jpg |
| Nominee1: | Franklin Pierce |
| Party1: | Democratic Party (United States) |
| Home State1: | New Hampshire |
| Running Mate1: | William R. King |
| Electoral Vote1: | 9 |
| Popular Vote1: | 38,817 |
| Percentage1: | 56.42% |
| Nominee2: | Winfield Scott |
| Party2: | Whig Party (United States) |
| Home State2: | New Jersey |
| Running Mate2: | William A. Graham |
| Electoral Vote2: | 0 |
| Popular Vote2: | 29,984 |
| Percentage2: | 43.58% |
| President | |
| Before Election: | Millard Fillmore |
| Before Party: | Whig Party (United States) |
| After Election: | Franklin Pierce |
| After Party: | Democratic Party (United States) |
The 1852 United States presidential election in Missouri took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Missouri by a margin of 12.84%.