See main article: 1852 United States presidential election.
| Election Name: | 1852 United States presidential election in Kentucky |
| Flag Year: | 1852 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1848 United States presidential election in Kentucky |
| Previous Year: | 1848 |
| Next Election: | 1856 United States presidential election in Kentucky |
| Next Year: | 1856 |
| Election Date: | November 2, 1852 |
| Image1: | Winfield Scott by Fredricks, 1862 (cropped).jpg |
| Nominee1: | Winfield Scott |
| Party1: | Whig Party (United States) |
| Home State1: | New Jersey |
| Running Mate1: | William A. Graham |
| Electoral Vote1: | 12 |
| Popular Vote1: | 57,428 |
| Percentage1: | 51.44% |
| Nominee2: | Franklin Pierce |
| Party2: | Democratic Party (United States) |
| Home State2: | New Hampshire |
| Running Mate2: | William R. King |
| Electoral Vote2: | 0 |
| Popular Vote2: | 53,949 |
| Percentage2: | 48.32% |
| Map Size: | 380px |
| President | |
| Before Election: | Millard Fillmore |
| Before Party: | Whig Party (United States) |
| After Election: | Franklin Pierce |
| After Party: | Democratic Party (United States) |
The 1852 United States presidential election in Kentucky took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for the Whig candidate, Winfield Scott, over Democratic candidate Franklin Pierce. Scott won Kentucky by a margin of 3.12%.
Kentucky was one of the four states to vote for Scott in the 1852 election with the other three being Massachusetts, Tennessee and Vermont.
With 51.44% of the popular vote, Kentucky would prove to be Scott's strongest victory in the nation.[1]