See main article: 1852 United States presidential election.
| Election Name: | 1852 United States presidential election in Iowa |
| Country: | Iowa |
| Flag Year: | 1852 |
| Type: | presidential |
| Ongoing: | no |
| Previous Election: | 1848 United States presidential election in Iowa |
| Previous Year: | 1848 |
| Next Election: | 1856 United States presidential election in Iowa |
| Next Year: | 1856 |
| Election Date: | November 2, 1852 |
| Image1: | Mathew Brady - Franklin Pierce (cropped).jpg |
| Nominee1: | Franklin Pierce |
| Party1: | Democratic Party (United States) |
| Home State1: | New Hampshire |
| Running Mate1: | William R. King |
| Electoral Vote1: | 4 |
| Popular Vote1: | 17,763 |
| Percentage1: | 50.23% |
| Nominee2: | Winfield Scott |
| Party2: | Whig Party (United States) |
| Home State2: | New Jersey |
| Running Mate2: | William A. Graham |
| Electoral Vote2: | 0 |
| Popular Vote2: | 15,856 |
| Percentage2: | 44.84% |
| Map Size: | 312px |
| President | |
| Before Election: | Millard Fillmore |
| Before Party: | Whig Party (United States) |
| After Election: | Franklin Pierce |
| After Party: | Democratic Party (United States) |
The 1852 United States presidential election in Iowa took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Iowa voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Iowa by a margin of 5.39%.
This would be the last time Iowa would back a Democratic presidential nominee until 1912, and the last time it would be with an absolute majority of the vote until 1932.