1852 United States presidential election in Indiana explained

See main article: 1852 United States presidential election.

Election Name:1852 United States presidential elections in Indiana
Country:Indiana
Flag Year:1852
Type:presidential
Ongoing:no
Previous Election:1848 United States presidential election in Indiana
Previous Year:1848
Next Election:1856 United States presidential election in Indiana
Next Year:1856
Election Date:November 2, 1852
Image1:Mathew Brady - Franklin Pierce (cropped).jpg
Nominee1:Franklin Pierce
Party1:Democratic Party (United States)
Home State1:New Hampshire
Running Mate1:William R. King
Electoral Vote1:13
Popular Vote1:95,340
Percentage1:52.05%
Nominee2:Winfield Scott
Party2:Whig Party (United States)
Home State2:New Jersey
Running Mate2:William A. Graham
Electoral Vote2:0
Popular Vote2:80,901
Percentage2:44.17%
Map Size:300px
President
Before Election:Millard Fillmore
Before Party:Whig Party (United States)
After Election:Franklin Pierce
After Party:Democratic Party (United States)

The 1852 United States presidential election in Indiana took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Indiana by a margin of 7.88%. This would be the last occasion Porter County voted for a Democratic presidential candidate until Bill Clinton won a plurality in 1996.[1]

See also

Notes and References

  1. Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, p. 117