| Election Name: | 1850 Rhode Island gubernatorial election |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1849 Rhode Island gubernatorial election |
| Previous Year: | 1849 |
| Next Election: | 1851 Rhode Island gubernatorial election |
| Next Year: | 1851 |
| Election Date: | 3 April 1850 |
| Nominee1: | Henry B. Anthony |
| Party1: | Whig Party (United States) |
| Popular Vote1: | 3,668 |
| Percentage1: | 80.16% |
| Nominee2: | Edward Harris |
| Party2: | Free Soil Party |
| Popular Vote2: | 773 |
| Percentage2: | 16.89% |
| Map Size: | 200px |
| Governor | |
| Before Election: | Henry B. Anthony |
| Before Party: | Whig Party (United States) |
| After Election: | Henry B. Anthony |
| After Party: | Whig Party (United States) |
The 1850 Rhode Island gubernatorial election was held on 3 April 1850 in order to elect the Governor of Rhode Island. Incumbent Whig Governor Henry B. Anthony won re-election against the Free Soil nominee Edward Harris in a rematch from the 1849 Rhode Island gubernatorial election.[1]
On election day, 3 April 1850, Henry B. Anthony won re-election by a margin of 2,895 votes against his opponent Edward Harris. Defeating Harris for a second time after Anthony's first election as Governor during the 1849 Rhode Island gubernatorial election. Retaining whig control of the office of Governor and being sworn in for his second term on 6 May 1850.[2]