| Election Name: | 1850 Maine gubernatorial election |
| Country: | Maine |
| Type: | Presidential |
| Ongoing: | no |
| Previous Election: | 1849 Maine gubernatorial election |
| Previous Year: | 1849 |
| Next Election: | 1852 Maine gubernatorial election |
| Next Year: | 1852 |
| Election Date: | 9 September 1850 |
| Nominee1: | John Hubbard |
| Party1: | Democratic Party (United States) |
| Popular Vote1: | 41,203 |
| Percentage1: | 51.08% |
| Nominee2: | William G. Crosby |
| Party2: | Whig Party (United States) |
| Popular Vote2: | 32,120 |
| Percentage2: | 39.82% |
| Nominee3: | George F. Talbot |
| Party3: | Free Soil Party (United States) |
| Popular Vote3: | 7,267 |
| Percentage3: | 9.01% |
| Governor | |
| Before Election: | John Hubbard |
| Before Party: | Democratic Party (United States) |
| After Election: | John Hubbard |
| After Party: | Democratic Party (United States) |
The 1850 Maine gubernatorial election was held on 9 September 1850 in order to elect the Governor of Maine. Incumbent Democratic Governor John Hubbard won re-election against Whig nominee William G. Crosby and Free Soil Party nominee George F. Talbot.[1]
On election day, 9 September 1850, incumbent Democratic governor John Hubbard won re-election by a margin of 9,083 votes against his foremost opponent Whig nominee William G. Crosby, thereby retaining Democratic control over the office of governor. Hubbard was sworn in for his second term on 8 May 1851.[2]